What is the derivative of sin(cos(2x)) ?

The derivative of sin(cos(2x)) is -2cos(cos(2x))sin(2x)

What is the first derivative of sin(cos(2x)) ?

The first derivative of sin(cos(2x)) is -2cos(cos(2x))sin(2x)

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\frac{d}{d x} (sin (cos (2 x)))

- 2 cos (cos (2 x)) sin (2 x)

Solution steps

\frac{d}{d x} (sin (cos (2 x)))

Apply the chain rule:

cos (cos (2 x)) \frac{d}{d x} (cos (2 x))

= cos (cos (2 x)) \frac{d}{d x} (cos (2 x))

\frac{d}{d x} (cos (2 x)) = - sin (2 x) \cdot 2

= cos (cos (2 x)) (- sin (2 x) \cdot 2)

Simplify

= - 2 cos (cos (2 x)) sin (2 x)

n = 1 \sum \infty \frac{1}{5 ^{n - 1}}

\frac{\partial}{\partial x} (cos (y - x))

x \to - 2 lim (7 x + 12)

\int \frac{ln ( 17 x )}{x} d x

\frac{\partial}{\partial x} ((\frac{x}{2})^{2})

What is the derivative of sin(cos(2x)) ?
The derivative of sin(cos(2x)) is -2cos(cos(2x))sin(2x)
What is the first derivative of sin(cos(2x)) ?
The first derivative of sin(cos(2x)) is -2cos(cos(2x))sin(2x)