What is the derivative of (x-1^2+y^2) ?

The derivative of (x-1^2+y^2) is 2(x-1)+2y(dy)/(dx)

What is the first derivative of (x-1^2+y^2) ?

The first derivative of (x-1^2+y^2) is 2(x-1)+2y(dy)/(dx)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} ((x - 1)^{2} + y^{2})

2 (x - 1) + 2 y \frac{d y}{d x}

Solution steps

\frac{d}{d x} ((x - 1)^{2} + y^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} ((x - 1)^{2}) + \frac{d}{d x} (y^{2})

\frac{d}{d x} ((x - 1)^{2}) = 2 (x - 1)

\frac{d}{d x} (y^{2}) = 2 y \frac{d y}{d x}

= 2 (x - 1) + 2 y \frac{d y}{d x}

f (x) = x^{3} + 2 x

2 x^{3} + 4 x^{2} - x + 2

y = \frac{x - 4}{x}

x \to - 10 lim (f (x))

x \to 3 - lim (\frac{x + 3}{x ^{2} - 9})

What is the derivative of (x-1^2+y^2) ?
The derivative of (x-1^2+y^2) is 2(x-1)+2y(dy)/(dx)
What is the first derivative of (x-1^2+y^2) ?
The first derivative of (x-1^2+y^2) is 2(x-1)+2y(dy)/(dx)