What is inverse oflaplace 4e^{-3s} ?

The answer to inverse oflaplace 4e^{-3s} is 4\delta(t-3)

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inverse oflaplace 4e^{-3s}

inverse laplace

4 e^{- 3 s}

4 δ (t - 3)

Solution steps

L^{- 1} {4 e^{- 3 s}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 4 L^{- 1} {e^{- 3 s}}

L^{- 1} {e^{- 3 s}} : δ (t - 3)

= 4 δ (t - 3)

\int 5 e^{7} d x

ln (x^{2} + 3)

\frac{d}{d x} (3 - 3 x^{2})

\frac{s + 4}{( s + 1 ) ^{2}}

\int \frac{1}{x} - \frac{2}{x ^{2} + 1} d x

What is inverse oflaplace 4e^{-3s} ?
The answer to inverse oflaplace 4e^{-3s} is 4\delta(t-3)