What is the derivative of ln(x^2+3) ?

The derivative of ln(x^2+3) is (2x)/(x^2+3)

What is the first derivative of ln(x^2+3) ?

The first derivative of ln(x^2+3) is (2x)/(x^2+3)

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derivative of

ln (x^{2} + 3)

\frac{2 x}{x ^{2} + 3}

Solution steps

\frac{d}{d x} (ln (x^{2} + 3))

Apply the chain rule:

\frac{1}{x ^{2} + 3} \frac{d}{d x} (x^{2} + 3)

= \frac{1}{x ^{2} + 3} \frac{d}{d x} (x^{2} + 3)

\frac{d}{d x} (x^{2} + 3) = 2 x

= \frac{1}{x ^{2} + 3} \cdot 2 x

Simplify

\frac{1}{x ^{2} + 3} \cdot 2 x : \frac{2 x}{x ^{2} + 3}

= \frac{2 x}{x ^{2} + 3}

\frac{d}{d x} (3 - 3 x^{2})

\frac{s + 4}{( s + 1 ) ^{2}}

\int \frac{1}{x} - \frac{2}{x ^{2} + 1} d x

\frac{( - 2 )}{( 6 s + s ^{2} )}

y d x = 2 (x + y) d y

What is the derivative of ln(x^2+3) ?
The derivative of ln(x^2+3) is (2x)/(x^2+3)
What is the first derivative of ln(x^2+3) ?
The first derivative of ln(x^2+3) is (2x)/(x^2+3)