What is the integral of ((7x^2+2x-7))/(x^3-x) ?

The integral of ((7x^2+2x-7))/(x^3-x) is 7ln|x|-ln|x+1|+ln|x-1|+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of ((7x^2+2x-7))/(x^3-x)

\int \frac{( 7 x ^{2} + 2 x - 7 )}{x ^{3} - x} d x

7 ln ∣ x ∣ - ln ∣ x + 1 ∣ + ln ∣ x - 1 ∣ + C

Solution steps

\int \frac{7 x ^{2} + 2 x - 7}{x ^{3} - x} d x

Take the partial fraction of

\frac{7 x ^{2} + 2 x - 7}{x ^{3} - x} : \frac{7}{x} - \frac{1}{x + 1} + \frac{1}{x - 1}

= \int \frac{7}{x} - \frac{1}{x + 1} + \frac{1}{x - 1} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{7}{x} d x - \int \frac{1}{x + 1} d x + \int \frac{1}{x - 1} d x

\int \frac{7}{x} d x = 7 ln ∣ x ∣

\int \frac{1}{x + 1} d x = ln ∣ x + 1 ∣

\int \frac{1}{x - 1} d x = ln ∣ x - 1 ∣

= 7 ln ∣ x ∣ - ln ∣ x + 1 ∣ + ln ∣ x - 1 ∣

Add a constant to the solution

= 7 ln ∣ x ∣ - ln ∣ x + 1 ∣ + ln ∣ x - 1 ∣ + C

\frac{\partial}{\partial x} (3 sin (x y))

\frac{d y}{d x} - 2 y = 4

(7 x^{2} - 14 x + 14) e^{x}

\frac{\partial}{\partial y} (y^{2} sin (x))

\frac{d}{d x} (ln (\frac{9 - x ^{2}}{9 + x ^{2}}))

What is the integral of ((7x^2+2x-7))/(x^3-x) ?
The integral of ((7x^2+2x-7))/(x^3-x) is 7ln|x|-ln|x+1|+ln|x-1|+C