What is the integral of 6sin^2(x)cos(x) ?

The integral of 6sin^2(x)cos(x) is 2sin^3(x)+C

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integral of 6sin^2(x)cos(x)

\int 6 sin^{2} (x) cos (x) d x

2 sin^{3} (x) + C

Solution steps

\int 6 sin^{2} (x) cos (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int sin^{2} (x) cos (x) d x

Apply u-substitution

: \int u^{2} d u

= 6 \cdot \int u^{2} d u

Apply the Power Rule

: \frac{u ^{3}}{3}

= 6 \cdot \frac{u ^{3}}{3}

Substitute back

u = sin (x)

= 6 \cdot \frac{sin ^{3} ( x )}{3}

Simplify

6 \cdot \frac{sin ^{3} ( x )}{3} : 2 sin^{3} (x)

= 2 sin^{3} (x)

Add a constant to the solution

= 2 sin^{3} (x) + C

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What is the integral of 6sin^2(x)cos(x) ?
The integral of 6sin^2(x)cos(x) is 2sin^3(x)+C