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Popular >

integral of 1/(y+5)

Solution

\int \frac{1}{y + 5} d y

Solution

ln ∣ y + 5 ∣ + C

Solution steps

\int \frac{1}{y + 5} d y

Apply u-substitution

: \int \frac{1}{u} d u

= \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= ln ∣ u ∣

Substitute back

u = y + 5

= ln ∣ y + 5 ∣

Add a constant to the solution

= ln ∣ y + 5 ∣ + C

Popular Examples

(\partial)/(\partial x)(yz+xz+xy)

\frac{\partial}{\partial x} (yz + x z + x y)

(\partial)/(\partial x)(8*y^{22})

\frac{\partial}{\partial x} (8 \cdot y^{22})

y^{''}-y^'=(3x^2+6x+1)e^x

y^{^{''}} - y^{^{'}} = (3 x^{2} + 6 x + 1) e^{x}

integral of x\sqrt[3]{2x+3}

limit as x approaches+1 of 3x^3-4x^2+x+9

x \to + 1 lim (3 x^{3} - 4 x^{2} + x + 9)

Frequently Asked Questions (FAQ)

What is the integral of 1/(y+5) ?
The integral of 1/(y+5) is ln|y+5|+C