What is the derivative of 1-1/(2x) ?

The derivative of 1-1/(2x) is 1/(2x^2)

What is the first derivative of 1-1/(2x) ?

The first derivative of 1-1/(2x) is 1/(2x^2)

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\frac{d}{d x} (1 - \frac{1}{2 x})

\frac{1}{2 x ^{2}}

Solution steps

\frac{d}{d x} (1 - \frac{1}{2 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (\frac{1}{2 x})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (\frac{1}{2 x}) = - \frac{1}{2 x ^{2}}

= 0 - (- \frac{1}{2 x ^{2}})

Simplify

= \frac{1}{2 x ^{2}}

\frac{d y}{d x} = \frac{x - 1}{y}

\int \frac{x ^{2}}{x ^{2} - 16} d x

\int \frac{1}{( a + b x ) ^{3}} d x

\int_{0}^{0.5} (300 x) d x

y^{^{''}} = 4 t^{3} + t

What is the derivative of 1-1/(2x) ?
The derivative of 1-1/(2x) is 1/(2x^2)
What is the first derivative of 1-1/(2x) ?
The first derivative of 1-1/(2x) is 1/(2x^2)