What is the limit as x approaches 2 of sqrt(4-x^2) ?

The limit as x approaches 2 of sqrt(4-x^2) is 0

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limit as x approaches 2 of sqrt(4-x^2)

x \to 2 lim (4 - x^{2})

0

Solution steps

x \to 2 lim (4 - x^{2})

Plug in the value

x = 2

= 4 - 2^{2}

Simplify

= 0

x \to 2 lim (5 x^{4})

x \to 2 lim (\frac{x - 2}{x + 2})

\int sin (3 π x) d x

n = 0 \sum \infty 8^{n}

\frac{d}{d x} (\frac{2}{( 5 x + 1 ) ^{3}})

What is the limit as x approaches 2 of sqrt(4-x^2) ?
The limit as x approaches 2 of sqrt(4-x^2) is 0