What is the solution for y^'sin(x)+ycos(x)=xsin(x) ?

The solution for y^'sin(x)+ycos(x)=xsin(x) is y=-(xcos(x))/(sin(x))+1+(c_{1})/(sin(x))

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y^'sin(x)+ycos(x)=xsin(x)

y^{^{'}} sin (x) + y cos (x) = x sin (x)

y = - \frac{x cos ( x )}{sin ( x )} + 1 + \frac{c _{1}}{sin ( x )}

Solution steps

y^{'} (x) sin (x) + y cos (x) = x sin (x)

Solve linear ODE:

y = - \frac{x cos ( x )}{sin ( x )} + 1 + \frac{c _{1}}{sin ( x )}

y = - \frac{x cos ( x )}{sin ( x )} + 1 + \frac{c _{1}}{sin ( x )}

x \to 1 lim (2 (x - 1))

\int_{- 2}^{0} x + 2 d x

\int \frac{t}{( t ^{2} + 1 ) ^{\frac{23}{2}}} d t

\int 6 ln (x) d x

2 x^{3} + 9 x^{2} + 9 x + 6

What is the solution for y^'sin(x)+ycos(x)=xsin(x) ?
The solution for y^'sin(x)+ycos(x)=xsin(x) is y=-(xcos(x))/(sin(x))+1+(c_{1})/(sin(x))