What is the derivative of 2+5tan^{-1}(x/2) ?

The derivative of 2+5tan^{-1}(x/2) is (10)/(x^2+4)

What is the first derivative of 2+5tan^{-1}(x/2) ?

The first derivative of 2+5tan^{-1}(x/2) is (10)/(x^2+4)

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derivative of

2 + 5 arctan (\frac{x}{2})

\frac{10}{x ^{2} + 4}

Solution steps

\frac{d}{d x} (2 + 5 arctan (\frac{x}{2}))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2) + \frac{d}{d x} (5 arctan (\frac{x}{2}))

\frac{d}{d x} (2) = 0

\frac{d}{d x} (5 arctan (\frac{x}{2})) = \frac{10}{x ^{2} + 4}

= 0 + \frac{10}{x ^{2} + 4}

Simplify

= \frac{10}{x ^{2} + 4}

\int (9 e^{x} - 9 x) d x

x^{3} e^{6 x^{3} + 8 x^{2} - 7}

\frac{d}{d x} (arcsin (x^{3}))

f (x) = \frac{f ( x )}{x ^{2} + 2}

\int_{1}^{16} \frac{4}{x} d x

What is the derivative of 2+5tan^{-1}(x/2) ?
The derivative of 2+5tan^{-1}(x/2) is (10)/(x^2+4)
What is the first derivative of 2+5tan^{-1}(x/2) ?
The first derivative of 2+5tan^{-1}(x/2) is (10)/(x^2+4)