What is derivative of f(x)=(f(x))/(x^2+2) ?

The answer to derivative of f(x)=(f(x))/(x^2+2) is (df)/(dx)=-(2xf)/(x^4+3x^2+2)

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derivative of f(x)=(f(x))/(x^2+2)

derivative of

f (x) = \frac{f ( x )}{x ^{2} + 2}

\frac{df}{d x} = - \frac{2 x f}{x ^{4} + 3 x ^{2} + 2}

Solution steps

f = \frac{f}{x ^{2} + 2}

Treat

f

f (x)

Differentiate both sides:

\frac{df}{d x} = \frac{\frac{df}{d x} ( x ^{2} + 2 ) - 2 x f}{( x ^{2} + 2 ) ^{2}}

Isolate

\frac{df}{d x} : \frac{df}{d x} = - \frac{2 x f}{x ^{4} + 3 x ^{2} + 2}

\frac{df}{d x} = - \frac{2 x f}{x ^{4} + 3 x ^{2} + 2}

\int_{1}^{16} \frac{4}{x} d x

x \to 0 lim (\frac{2 x}{x ^{2} - 5 x})

\frac{\partial}{\partial x} (4 x ln (x) y)

\int (2 x + y)^{8} d x

x \to 0 + lim ((x)^{- x^{2}})

What is derivative of f(x)=(f(x))/(x^2+2) ?
The answer to derivative of f(x)=(f(x))/(x^2+2) is (df)/(dx)=-(2xf)/(x^4+3x^2+2)