What is the derivative of g(x)=sqrt(7-3x) ?

The derivative of g(x)=sqrt(7-3x) is -3/(2sqrt(7-3x))

What is the first derivative of g(x)=sqrt(7-3x) ?

The first derivative of g(x)=sqrt(7-3x) is -3/(2sqrt(7-3x))

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derivative of

g (x) = 7 - 3 x

- \frac{3}{2 7 - 3 x}

Solution steps

\frac{d}{d x} (7 - 3 x)

Apply the chain rule:

\frac{1}{2 7 - 3 x} \frac{d}{d x} (7 - 3 x)

= \frac{1}{2 7 - 3 x} \frac{d}{d x} (7 - 3 x)

\frac{d}{d x} (7 - 3 x) = - 3

= \frac{1}{2 7 - 3 x} (- 3)

Simplify

\frac{1}{2 7 - 3 x} (- 3) : - \frac{3}{2 7 - 3 x}

= - \frac{3}{2 7 - 3 x}

400 - 3 P + 4 T + 0.6 A

\frac{d y}{d x} = \frac{- x}{y}

x \to \frac{5}{4} lim (\frac{16 x ^{2} - 25}{4 x - 5})

\frac{d}{d x} (1 - cos (x^{3}))

(t - 3)^{3}

What is the derivative of g(x)=sqrt(7-3x) ?
The derivative of g(x)=sqrt(7-3x) is -3/(2sqrt(7-3x))
What is the first derivative of g(x)=sqrt(7-3x) ?
The first derivative of g(x)=sqrt(7-3x) is -3/(2sqrt(7-3x))