What is the derivative of sin(x^2-x) ?

The derivative of sin(x^2-x) is cos(x^2-x)(2x-1)

What is the first derivative of sin(x^2-x) ?

The first derivative of sin(x^2-x) is cos(x^2-x)(2x-1)

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\frac{d}{d x} (sin (x^{2} - x))

cos (x^{2} - x) (2 x - 1)

Solution steps

\frac{d}{d x} (sin (x^{2} - x))

Apply the chain rule:

cos (x^{2} - x) \frac{d}{d x} (x^{2} - x)

= cos (x^{2} - x) \frac{d}{d x} (x^{2} - x)

\frac{d}{d x} (x^{2} - x) = 2 x - 1

= cos (x^{2} - x) (2 x - 1)

\int tan (x) sec^{6} (x) d x

y = (1 + 3 x)^{8}, (0, 1)

\int (x^{2} e^{2 x}) d x

x \to - \infty lim (f (x))

\frac{d}{d x} (4 x^{3} - 156 x^{2} + 1512 x)

What is the derivative of sin(x^2-x) ?
The derivative of sin(x^2-x) is cos(x^2-x)(2x-1)
What is the first derivative of sin(x^2-x) ?
The first derivative of sin(x^2-x) is cos(x^2-x)(2x-1)