What is the tangent of y=(1+3x)^8,(0,1) ?

The tangent of y=(1+3x)^8,(0,1) is y=24x+1

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tangent of y=(1+3x)^8,(0,1)

tangent of

y = (1 + 3 x)^{8}, (0, 1)

y = 24 x + 1

Solution steps

Find the slope of

y = (1 + 3 x)^{8} : \frac{d y}{d x} = 24 (1 + 3 x)^{7}

Compute the slope of

y = (1 + 3 x)^{8}

(0, 1) : m = 24

Find the line with slope m=

24

and passing through

(0, 1) : y = 24 x + 1

y = 24 x + 1

\int (x^{2} e^{2 x}) d x

x \to - \infty lim (f (x))

\frac{d}{d x} (4 x^{3} - 156 x^{2} + 1512 x)

\frac{d}{d x} (y e^{x^{2}})

6 cos (3 x)

What is the tangent of y=(1+3x)^8,(0,1) ?
The tangent of y=(1+3x)^8,(0,1) is y=24x+1