What is the derivative of y=x^2+3x^2ln(x) ?

The derivative of y=x^2+3x^2ln(x) is 5x+6xln(x)

What is the first derivative of y=x^2+3x^2ln(x) ?

The first derivative of y=x^2+3x^2ln(x) is 5x+6xln(x)

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derivative of

y = x^{2} + 3 x^{2} ln (x)

5 x + 6 x ln (x)

Solution steps

\frac{d}{d x} (x^{2} + 3 x^{2} ln (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (3 x^{2} ln (x))

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x^{2} ln (x)) = 3 (2 x ln (x) + x)

= 2 x + 3 (2 x ln (x) + x)

Simplify

2 x + 3 (2 x ln (x) + x) : 5 x + 6 x ln (x)

= 5 x + 6 x ln (x)

\int \frac{e ^{2 x} - 7}{e ^{2 x}} d x

\frac{7}{8 t ^{4}}

\frac{d}{d x} (x^{2} + c)

x \to 2 lim (\frac{2 + x}{2 - 4})

n = 0 \sum \infty 2 (\frac{1}{3 ^{n}})

What is the derivative of y=x^2+3x^2ln(x) ?
The derivative of y=x^2+3x^2ln(x) is 5x+6xln(x)
What is the first derivative of y=x^2+3x^2ln(x) ?
The first derivative of y=x^2+3x^2ln(x) is 5x+6xln(x)