What is the derivative of f(x)=(-x^2-4)^2 ?

The derivative of f(x)=(-x^2-4)^2 is -4x(-x^2-4)

What is the first derivative of f(x)=(-x^2-4)^2 ?

The first derivative of f(x)=(-x^2-4)^2 is -4x(-x^2-4)

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derivative of

f (x) = (- x^{2} - 4)^{2}

- 4 x (- x^{2} - 4)

Solution steps

\frac{d}{d x} ((- x^{2} - 4)^{2})

Apply the chain rule:

2 (- x^{2} - 4) \frac{d}{d x} (- x^{2} - 4)

= 2 (- x^{2} - 4) \frac{d}{d x} (- x^{2} - 4)

\frac{d}{d x} (- x^{2} - 4) = - 2 x

= 2 (- x^{2} - 4) (- 2 x)

Simplify

= - 4 x (- x^{2} - 4)

\frac{d}{d x} (3 x^{2} - \frac{1}{24} ln (x))

\int \frac{1}{x ^{2} + 4 x + 20} d x

x \to 1 lim (e^{x})

x \to 5 lim (x^{- 1})

\frac{d}{d x} (2 x - 4 sin (x))

What is the derivative of f(x)=(-x^2-4)^2 ?
The derivative of f(x)=(-x^2-4)^2 is -4x(-x^2-4)
What is the first derivative of f(x)=(-x^2-4)^2 ?
The first derivative of f(x)=(-x^2-4)^2 is -4x(-x^2-4)