What is the tangent of f(x)=7sqrt(x),\at x=4 ?

The tangent of f(x)=7sqrt(x),\at x=4 is y= 7/4 x+7

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tangent of f(x)=7sqrt(x),\at x=4

tangent of

f (x) = 7 x, at x = 4

y = \frac{7}{4} x + 7

Solution steps

Find the tangent point:

(4, 14)

Find the slope of

f (x) = 7 x : \frac{df ( x )}{d x} = \frac{7}{2 x}

Compute the slope of

f (x) = 7 x

x = 4 : m = \frac{7}{4}

Find the line with slope m=

\frac{7}{4}

and passing through

(4, 14) : y = \frac{7}{4} x + 7

y = \frac{7}{4} x + 7

n = 5 \sum \infty \frac{n ^{3}}{2 ^{n}}

f^{^{''}} (x) = 2

x \to - \infty lim (x + \frac{1}{x})

\int_{0}^{\frac{π}{4}} sec (x) d x

\int 24 x^{5} d x

What is the tangent of f(x)=7sqrt(x),\at x=4 ?
The tangent of f(x)=7sqrt(x),\at x=4 is y= 7/4 x+7