What is the tangent of y=(x^2)/(x+2),(2,1) ?

The tangent of y=(x^2)/(x+2),(2,1) is y= 3/4 x-1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y=(x^2)/(x+2),(2,1)

tangent of

y = \frac{x ^{2}}{x + 2}, (2, 1)

y = \frac{3}{4} x - \frac{1}{2}

Solution steps

Find the slope of

y = \frac{x ^{2}}{x + 2} : \frac{d y}{d x} = \frac{x ^{2} + 4 x}{( x + 2 ) ^{2}}

Compute the slope of

y = \frac{x ^{2}}{x + 2}

(2, 1) : m = \frac{3}{4}

Find the line with slope m=

\frac{3}{4}

and passing through

(2, 1) : y = \frac{3}{4} x - \frac{1}{2}

y = \frac{3}{4} x - \frac{1}{2}

\frac{d}{d x} (x - 2 x^{2} + 1)

x \to - 2 lim (\frac{( x ^{2} - 3 x - 10 )}{( x ^{2} + 5 x + 6 )})

\frac{d}{d x} (2 (6 x^{2} - 7 x) (12 x - 7))

\int e^{- s x} (2 - x) d x

x \to 1 lim (\frac{1}{x ^{3} - 1})

What is the tangent of y=(x^2)/(x+2),(2,1) ?
The tangent of y=(x^2)/(x+2),(2,1) is y= 3/4 x-1/2