What is the derivative of f(x)\sqrt[5]{x} ?

The derivative of f(x)\sqrt[5]{x} is x^{6/5}

What is the first derivative of f(x)\sqrt[5]{x} ?

The first derivative of f(x)\sqrt[5]{x} is x^{6/5}

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derivative of

x^{\frac{6}{5}}

Solution steps

Simplify

= \frac{d}{df} (f x^{\frac{6}{5}})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x^{\frac{6}{5}} \frac{df}{df}

Apply the common derivative:

\frac{df}{df} = 1

= x^{\frac{6}{5}} \cdot 1

Simplify

= x^{\frac{6}{5}}

y = \frac{x ^{2}}{x + 2}, (2, 1)

\frac{d}{d x} (x - 2 x^{2} + 1)

x \to - 2 lim (\frac{( x ^{2} - 3 x - 10 )}{( x ^{2} + 5 x + 6 )})

\frac{d}{d x} (2 (6 x^{2} - 7 x) (12 x - 7))

\int e^{- s x} (2 - x) d x

What is the derivative of f(x)\sqrt[5]{x} ?
The derivative of f(x)\sqrt[5]{x} is x^{6/5}
What is the first derivative of f(x)\sqrt[5]{x} ?
The first derivative of f(x)\sqrt[5]{x} is x^{6/5}