What is the integral from 1/2 to 3 of 1/(x^2) ?

The integral from 1/2 to 3 of 1/(x^2) is 5/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1/2 to 3 of 1/(x^2)

\int_{\frac{1}{2}}^{3} \frac{1}{x ^{2}} d x

\frac{5}{3}

Decimal Notation

1.66666 \dots

Solution steps

\int_{\frac{1}{2}}^{3} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{\frac{1}{2}}^{3}

= [- \frac{1}{x}]_{\frac{1}{2}}^{3}

Compute the boundaries:

\frac{5}{3}

= \frac{5}{3}

\int_{0}^{2 π} (x^{2} sin (2 x)) d x

t \to 0 lim (\frac{sin ( 7 t )}{t})

\frac{d}{d x} (cos (x) + i sin (x))

y = x^{3} - 3 x + 2, (2, 4)

\int_{- \infty}^{- 1} e^{- 2 x} d x

What is the integral from 1/2 to 3 of 1/(x^2) ?
The integral from 1/2 to 3 of 1/(x^2) is 5/3