What is the limit as t approaches 0 of (sin(7t))/t ?

The limit as t approaches 0 of (sin(7t))/t is 7

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limit as t approaches 0 of (sin(7t))/t

t \to 0 lim (\frac{sin ( 7 t )}{t})

7

Solution steps

t \to 0 lim (\frac{sin ( 7 t )}{t})

Apply L'Hopital's Rule

: t \to 0 lim (\frac{cos ( 7 t ) \cdot 7}{1})

= t \to 0 lim (\frac{cos ( 7 t ) \cdot 7}{1})

Plug in the value

t = 0

= \frac{cos ( 7 \cdot 0 ) \cdot 7}{1}

Simplify

\frac{cos ( 7 \cdot 0 ) \cdot 7}{1} : 7

= 7

\frac{d}{d x} (cos (x) + i sin (x))

y = x^{3} - 3 x + 2, (2, 4)

\int_{- \infty}^{- 1} e^{- 2 x} d x

\int \frac{3 x ^{3} - 3 x ^{2} + 1}{x ^{2} - x} d x

\int x arcsin (d) x d x

What is the limit as t approaches 0 of (sin(7t))/t ?
The limit as t approaches 0 of (sin(7t))/t is 7