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Popular >

y^'=3y-2x

Solution

y^{^{'}} = 3 y - 2 x

Solution

y = \frac{2 ( 3 x + 1 )}{9} + c_{1} e^{3 x}

Solution steps

y^{'} (x) = 3 y - 2 x

Solve linear ODE:

y = \frac{2 ( 3 x + 1 )}{9} + c_{1} e^{3 x}

y = \frac{2 ( 3 x + 1 )}{9} + c_{1} e^{3 x}

Popular Examples

area 5cos(7x),5-5cos(7x),[0, pi/7 ]area

5 cos (7 x), 5 - 5 cos (7 x), [0, \frac{π}{7}]

y^'+y/(6.96)=0.0025862069

y^{^{'}} + \frac{y}{6.96} = 0.0025862069

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\frac{d}{d x} (ln (x^{\frac{1}{5}}))

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\int x^{2} + x^{- 2} d x

sin(2x)dx+cos(6y)dy=0

sin (2 x) d x + cos (6 y) d y = 0

Frequently Asked Questions (FAQ)

What is the solution for y^'=3y-2x ?
The solution for y^'=3y-2x is y=(2(3x+1))/9+c_{1}e^{3x}