What is the first d/(dt)(e^{2t}) ?

The first d/(dt)(e^{2t}) is e^{2t}*2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

d/(dt)(e^{2t})

\frac{d}{d t} (e^{2 t})

e^{2 t} \cdot 2

Solution steps

\frac{d}{d t} (e^{2 t})

Apply the chain rule:

e^{2 t} \frac{d}{d t} (2 t)

= e^{2 t} \frac{d}{d t} (2 t)

\frac{d}{d t} (2 t) = 2

= e^{2 t} \cdot 2

(1 - x)^{- \frac{1}{2}}, 4

y = x^{2} - 3

f (x) = x sin (\frac{4}{x})

\frac{d}{d x} (3 x^{2} - e^{- x})

x = y^{2}, x = y^{2} + 2