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Popular >

area x=y^2,x=y^2+2

Solution

area

x = y^{2}, x = y^{2} + 2

Solution

No Solution

Solution steps

Isolate

y

for

x = y^{2} : y = x, y = - x

Isolate

y

for

x = y^{2} + 2 : y = x - 2, y = - x - 2

f_{1} (x) = x

f_{2} (x) = - x

To find the intersection points solve

f_{i} (x) = f_{j} (x)

x = - x : x = 0

x = x - 2 :

No Solution for

x \in R

x = - x - 2 :

No Solution for

x \in R

- x = x - 2 :

No Solution for

x \in R

- x = - x - 2 :

No Solution for

x \in R

x - 2 = - x - 2 : x = 2

Curves not bounded

= No Solution

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tangent of f(x)=3x-2sqrt(x),\at x=1 tangent of

f (x) = 3 x - 2 x, at x = 1

(\partial)/(\partial y)((9y)/(x^5))

\frac{\partial}{\partial y} (\frac{9 y}{x ^{5}})

y^{^{''}} + 22 y = 0

(\partial)/(\partial y)(x^2+xy+y^2)

\frac{\partial}{\partial y} (x^{2} + x y + y^{2})

Frequently Asked Questions (FAQ)

What is area x=y^2,x=y^2+2 ?
The answer to area x=y^2,x=y^2+2 is No Solution