What is the derivative of 3x^2-e^{-x} ?

The derivative of 3x^2-e^{-x} is 6x+e^{-x}

What is the first derivative of 3x^2-e^{-x} ?

The first derivative of 3x^2-e^{-x} is 6x+e^{-x}

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\frac{d}{d x} (3 x^{2} - e^{- x})

6 x + e^{- x}

Solution steps

\frac{d}{d x} (3 x^{2} - e^{- x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (e^{- x})

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (e^{- x}) = - e^{- x}

= 6 x - (- e^{- x})

Simplify

= 6 x + e^{- x}

x = y^{2}, x = y^{2} + 2

arcsin (cos (x^{3}))

f (x) = 3 x - 2 x, at x = 1

\frac{\partial}{\partial y} (\frac{9 y}{x ^{5}})

y^{^{''}} + 22 y = 0

What is the derivative of 3x^2-e^{-x} ?
The derivative of 3x^2-e^{-x} is 6x+e^{-x}
What is the first derivative of 3x^2-e^{-x} ?
The first derivative of 3x^2-e^{-x} is 6x+e^{-x}