What is the derivative of f(x)=e^6+ln(4) ?

The derivative of f(x)=e^6+ln(4) is 0

What is the first derivative of f(x)=e^6+ln(4) ?

The first derivative of f(x)=e^6+ln(4) is 0

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derivative of

f (x) = e^{6} + ln (4)

0

Solution steps

\frac{d}{d x} (e^{6} + ln (4))

e^{6} + ln (4) = e^{6} + 2 ln (2)

= \frac{d}{d x} (e^{6} + 2 ln (2))

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

\frac{d}{d x} (4 x^{3} - 24 x^{2} + 36 x)

\frac{d P}{d t} = 1 P (500 - P)

- sin (3 x)

x \cdot y^{^{'}} + y = \frac{1}{y ^{2}}

\int 2 x 1 + 4 x^{2} d x

What is the derivative of f(x)=e^6+ln(4) ?
The derivative of f(x)=e^6+ln(4) is 0
What is the first derivative of f(x)=e^6+ln(4) ?
The first derivative of f(x)=e^6+ln(4) is 0