What is the integral of e^{x^2+4x+3}(x+2) ?

The integral of e^{x^2+4x+3}(x+2) is 1/2 e^{x^2+4x+3}+C

Popular >

integral of e^{x^2+4x+3}(x+2)

\int e^{x^{2} + 4 x + 3} (x + 2) d x

\frac{1}{2} e^{x^{2} + 4 x + 3} + C

Solution steps

\int e^{x^{2} + 4 x + 3} (x + 2) d x

Apply u-substitution

: \int \frac{e ^{u}}{2} d u

= \int \frac{e ^{u}}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= \frac{1}{2} e^{u}

Substitute back

u = x^{2} + 4 x + 3

= \frac{1}{2} e^{x^{2} + 4 x + 3}

Add a constant to the solution

= \frac{1}{2} e^{x^{2} + 4 x + 3} + C

\frac{\partial}{\partial x} (x^{2} z^{2} sin (4 y))

\frac{\partial}{\partial y} (\frac{x y}{( x - y )})

x \to 4 lim (\frac{x ^{2} - 5}{x + 5})

f (x) = 3 x^{2} - ln (x), (1, 3)

f (x) = x^{5}, at x = 4

What is the integral of e^{x^2+4x+3}(x+2) ?
The integral of e^{x^2+4x+3}(x+2) is 1/2 e^{x^2+4x+3}+C