What is the solution for (17+x^2)y^'-2xy=0 ?

The solution for (17+x^2)y^'-2xy=0 is y=17e^{c_{1}}+e^{c_{1}}x^2

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(17+x^2)y^'-2xy=0

(17 + x^{2}) y^{^{'}} - 2 x y = 0

y = 17 e^{c_{1}} + e^{c_{1}} x^{2}

Solution steps

(17 + x^{2}) y^{'} (x) - 2 x y = 0

Solve separable ODE:

y = 17 e^{c_{1}} + e^{c_{1}} x^{2}

y = 17 e^{c_{1}} + e^{c_{1}} x^{2}

\frac{d}{d x} (\frac{cos ( x )}{1 + x ^{2}})

x \to 0 lim (\frac{1}{2 x ^{2}})

\frac{d ^{2}}{d x ^{2}} (cos^{2} (3 π x))

\int x^{28} e^{x^{29}} d x

\int ln (\frac{1 - x}{1 + x}) d x

What is the solution for (17+x^2)y^'-2xy=0 ?
The solution for (17+x^2)y^'-2xy=0 is y=17e^{c_{1}}+e^{c_{1}}x^2