What is area y=e^x,y=10e^{-x}+3,x=0 ?

The answer to area y=e^x,y=10e^{-x}+3,x=0 is 3ln(5)+4

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area y=e^x,y=10e^{-x}+3,x=0

area

y = e^{x}, y = 10 e^{- x} + 3, x = 0

3 ln (5) + 4

Decimal Notation

8.82831 \dots

Solution steps

Apply the area formula:

\int_{0}^{l n (5)} e^{x} - (10 e^{- x} + 3) d x

Solve

\int_{0}^{l n (5)} e^{x} - (10 e^{- x} + 3) d x : 3 ln (5) + 4

The area is:

= 3 ln (5) + 4

x \to 1 lim (x^{4})

\frac{8}{x ^{2}}

f (x) = x^{2} - 7, (5, 18)

x \to 4 lim (5 x - 2)

\int \frac{3}{x ( x ^{4} + 8 )} d x

What is area y=e^x,y=10e^{-x}+3,x=0 ?
The answer to area y=e^x,y=10e^{-x}+3,x=0 is 3ln(5)+4