What is the derivative of f(x)=ln(x-2) ?

The derivative of f(x)=ln(x-2) is 1/(x-2)

What is the first derivative of f(x)=ln(x-2) ?

The first derivative of f(x)=ln(x-2) is 1/(x-2)

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derivative of

f (x) = ln (x - 2)

\frac{1}{x - 2}

Solution steps

\frac{d}{d x} (ln (x - 2))

Apply the chain rule:

\frac{1}{x - 2} \frac{d}{d x} (x - 2)

= \frac{1}{x - 2} \frac{d}{d x} (x - 2)

\frac{d}{d x} (x - 2) = 1

= \frac{1}{x - 2} \cdot 1

Simplify

= \frac{1}{x - 2}

y = 2 cos (x + y)

\frac{d ^{2}}{d x ^{2}} (x^{2} - y^{2})

\frac{d}{d x} (y z (x)^{3})

\frac{\partial}{\partial y} (0)

\frac{d}{d x} (2 e^{2 x} \cdot x)

What is the derivative of f(x)=ln(x-2) ?
The derivative of f(x)=ln(x-2) is 1/(x-2)
What is the first derivative of f(x)=ln(x-2) ?
The first derivative of f(x)=ln(x-2) is 1/(x-2)