What is the derivative of-2x^{-1} ?

The derivative of-2x^{-1} is 2/(x^2)

What is the first derivative of-2x^{-1} ?

The first derivative of-2x^{-1} is 2/(x^2)

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\frac{d}{d x} (- 2 x^{- 1})

\frac{2}{x ^{2}}

Solution steps

\frac{d}{d x} (- 2 x^{- 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{d}{d x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 2 (- 1 \cdot x^{- 1 - 1})

Simplify

- 2 (- 1 \cdot x^{- 1 - 1}) : \frac{2}{x ^{2}}

= \frac{2}{x ^{2}}

y^{^{'}} = 2 x - y, y (0) = 1

y^{^{'}} = x^{9} + 1

h (t) = t^{2} (7 t + 8)^{3}

\frac{d ^{2}}{d x ^{2}} (7 sec (x))

\frac{\partial}{\partial x} (\frac{( 2 + t ^{2} )}{3 x - x ^{3}})

What is the derivative of-2x^{-1} ?
The derivative of-2x^{-1} is 2/(x^2)
What is the first derivative of-2x^{-1} ?
The first derivative of-2x^{-1} is 2/(x^2)