What is area x^2,x^4-3x^2,-2,2 ?

The answer to area x^2,x^4-3x^2,-2,2 is 128/15

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area x^2,x^4-3x^2,-2,2

area

x^{2}, x^{4} - 3 x^{2}, - 2, 2

\frac{128}{15}

Decimal Notation

8.53333 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{2} x^{2} - (x^{4} - 3 x^{2}) d x

Solve

\int_{- 2}^{2} x^{2} - (x^{4} - 3 x^{2}) d x : \frac{128}{15}

The area is:

= \frac{128}{15}

x \to a lim (x^{s i n (x)})

\frac{x ^{2}}{2 x + 4}

\frac{d x}{d t} - 2 x = x^{3}

\frac{d}{d x} (ln (x) - 2 x^{2})

\frac{d}{d x} (\frac{5 x}{x ^{2} + 1})