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Popular >

y^'=yxe^{x^2}-y

Solution

y^{^{'}} = y x e^{x^{2}} - y

Solution

y = e^{\frac{1}{2} e^{x^{2}} - x + c_{1}}

Solution steps

y^{'} (x) = y x e^{x^{2}} - y

Solve separable ODE:

y = e^{\frac{1}{2} e^{x^{2}} - x + c_{1}}

y = e^{\frac{1}{2} e^{x^{2}} - x + c_{1}}

Popular Examples

limit as x approaches 0-of x^2ln(x)

x \to 0 - lim (x^{2} ln (x))

y^{^{'}} - x^{2} = 2 x^{2} y

derivative of (x^2/(10+x))

\frac{d}{d x} (\frac{x ^{2}}{10 + x})

derivative of sqrt(18x)derivative of

18 x

tangent of f(x)=5x-4x^2,(-2,-26)tangent of

f (x) = 5 x - 4 x^{2}, (- 2, - 26)

Frequently Asked Questions (FAQ)

What is the solution for y^'=yxe^{x^2}-y ?
The solution for y^'=yxe^{x^2}-y is y=e^{1/2 e^{x^2}-x+c_{1}}