What is area v(t)=sqrt(t)-13,[0,3] ?

The answer to area v(t)=sqrt(t)-13,[0,3] is -2sqrt(3)+39

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area v(t)=sqrt(t)-13,[0,3]

area

v (t) = t - 13, [0, 3]

- 23 + 39

Decimal Notation

35.53589 \dots

Solution steps

Apply the area formula:

\int_{0}^{3} t - 13 d t

Solve

\int_{0}^{3} t - 13 d t : - 23 + 39

The area is:

= - 23 + 39

\int \frac{3 x + 2}{x + 1} d x

2 x^{3} + 10 x^{2} + 22 x - 3, x^{3} - x^{2} - 6 x - 3, - 2, - 2

\frac{d}{d x} (\frac{2}{( 1 + x ) ^{3}})

y = x^{2} + x, (1, 2)

f (x) = - 3 cos (x), at x = \frac{π}{2}

What is area v(t)=sqrt(t)-13,[0,3] ?
The answer to area v(t)=sqrt(t)-13,[0,3] is -2sqrt(3)+39