What is the integral of 1/(16x) ?

The integral of 1/(16x) is 1/16 ln|x|+C

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integral of 1/(16x)

\int \frac{1}{16 x} d x

\frac{1}{16} ln ∣ x ∣ + C

Solution steps

\int \frac{1}{16 x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{16} \cdot \int \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= \frac{1}{16} ln ∣ x ∣

Add a constant to the solution

= \frac{1}{16} ln ∣ x ∣ + C

\frac{\partial}{\partial x} (y^{3} sin (3 x))

g (x) = \frac{( π ^{2} )}{x ^{2} + 4 x}

\frac{d}{d x} (sec (x) - x)

y = x^{2} + 4 x - 11, (2, - 1)

f (x) = 1 + x, x = 0