What is the derivative of cos(2x+pi) ?

The derivative of cos(2x+pi) is 2sin(2x)

What is the first derivative of cos(2x+pi) ?

The first derivative of cos(2x+pi) is 2sin(2x)

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derivative of

cos (2 x + π)

2 sin (2 x)

Solution steps

\frac{d}{d x} (cos (2 x + π))

Simplify

cos (2 x + π) : - cos (2 x)

= \frac{d}{d x} (- cos (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (cos (2 x))

Apply the chain rule:

- sin (2 x) \frac{d}{d x} (2 x)

= - sin (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= - (- sin (2 x) \cdot 2)

Simplify

= 2 sin (2 x)

5 t y^{^{'}} + (10 + 5 t (\frac{2 ( t - 7 )}{7 t})) y = 0

\frac{\partial}{\partial x} (10 sin (x y))

\int (12 x + 7) d x

x \to 4 lim (\frac{1}{x - 3})

- \frac{170 t}{( t + 4 ) ^{2}}

What is the derivative of cos(2x+pi) ?
The derivative of cos(2x+pi) is 2sin(2x)
What is the first derivative of cos(2x+pi) ?
The first derivative of cos(2x+pi) is 2sin(2x)