What is the derivative of f(x)= 1/(x-4) ?

The derivative of f(x)= 1/(x-4) is -1/((x-4)^2)

What is the first derivative of f(x)= 1/(x-4) ?

The first derivative of f(x)= 1/(x-4) is -1/((x-4)^2)

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derivative of

f (x) = \frac{1}{x - 4}

- \frac{1}{( x - 4 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{x - 4})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((x - 4)^{- 1})

Apply the chain rule:

- \frac{1}{( x - 4 ) ^{2}} \frac{d}{d x} (x - 4)

= - \frac{1}{( x - 4 ) ^{2}} \frac{d}{d x} (x - 4)

\frac{d}{d x} (x - 4) = 1

= - \frac{1}{( x - 4 ) ^{2}} \cdot 1

Simplify

= - \frac{1}{( x - 4 ) ^{2}}

\frac{d ^{3}}{d x ^{3}} (\frac{2}{x ^{2}})

\frac{\partial}{\partial x} (2 x e^{- y})

y^{^{'}} + 6 y = 60, y (1) = 60

\int \frac{1}{1 - tan ^{2} ( x )} d x

\frac{d y}{d x} = \frac{x + y + 2}{x + y - 4}

What is the derivative of f(x)= 1/(x-4) ?
The derivative of f(x)= 1/(x-4) is -1/((x-4)^2)
What is the first derivative of f(x)= 1/(x-4) ?
The first derivative of f(x)= 1/(x-4) is -1/((x-4)^2)