What is the solution for P-P^2=(dP)/(dt) ?

The solution for P-P^2=(dP)/(dt) is P=-(e^{t+c_{1}})/(1-e^{t+c_{1)}}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

P-P^2=(dP)/(dt)

P - P^{2} = \frac{d P}{d t}

P = - \frac{e ^{t + c_{1}}}{1 - e ^{t + c_{1}}}

Solution steps

P - P^{2} = \frac{d P}{d t}

Solve separable ODE:

P = - \frac{e ^{t + c_{1}}}{1 - e ^{t + c_{1}}}

P = - \frac{e ^{t + c_{1}}}{1 - e ^{t + c_{1}}}

\frac{\partial}{\partial x} (e^{\frac{- y}{x}})

x^{2} y^{^{'}} - 2 x y = 3 y^{4}

\int \frac{x}{8} 64 + x^{2} d x

y = x^{2} + 2, (1, 3)

What is the solution for P-P^2=(dP)/(dt) ?
The solution for P-P^2=(dP)/(dt) is P=-(e^{t+c_{1}})/(1-e^{t+c_{1)}}