What is the sum from n=1 to infinity of n^4(1+n^5)^2 ?

The sum from n=1 to infinity of n^4(1+n^5)^2 is diverges

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sum from n=1 to infinity of n^4(1+n^5)^2

n = 1 \sum \infty n^{4} (1 + n^{5})^{2}

diverges

Solution steps

n = 1 \sum \infty n^{4} (1 + n^{5})^{2}

Apply Series Divergence Test:

diverges

= diverges

x \to 0 lim (\frac{sin ( 40 )}{x})

f (x) = \frac{3}{x + 3}

\int cos (5 x) cos (7 x) d x

\int_{0}^{3} - x^{2} + 9 d x

y^{^{'}} = \frac{( y ^{2} - 1 )}{2 x}, y (1) = - 2

What is the sum from n=1 to infinity of n^4(1+n^5)^2 ?
The sum from n=1 to infinity of n^4(1+n^5)^2 is diverges