What is (\partial)/(\partial x)(x^2-4xy+y^3+4y) ?

The answer to (\partial)/(\partial x)(x^2-4xy+y^3+4y) is 2x-4y

Popular >

(\partial)/(\partial x)(x^2-4xy+y^3+4y)

\frac{\partial}{\partial x} (x^{2} - 4 x y + y^{3} + 4 y)

2 x - 4 y

Solution steps

\frac{\partial}{\partial x} (x^{2} - 4 x y + y^{3} + 4 y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) - \frac{\partial}{\partial x} (4 x y) + \frac{\partial}{\partial x} (y^{3}) + \frac{\partial}{\partial x} (4 y)

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (4 x y) = 4 y

\frac{\partial}{\partial x} (y^{3}) = 0

\frac{\partial}{\partial x} (4 y) = 0

= 2 x - 4 y + 0 + 0

Simplify

= 2 x - 4 y

\frac{- 200 ln ( \frac{f}{40} )}{( f + 20 )}

\frac{d}{d x} (\frac{y}{1 + x ^{2}})

\int \frac{x ^{3}}{5} d x

\int_{1}^{\infty} \frac{1}{n ^{2}}

x, 2 - x, 0

What is (\partial)/(\partial x)(x^2-4xy+y^3+4y) ?
The answer to (\partial)/(\partial x)(x^2-4xy+y^3+4y) is 2x-4y