What is the tangent of 2xy^3+xy=18,(6,1) ?

The tangent of 2xy^3+xy=18,(6,1) is y=-1/14 x+10/7

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tangent of 2xy^3+xy=18,(6,1)

tangent of

2 x y^{3} + x y = 18, (6, 1)

y = - \frac{1}{14} x + \frac{10}{7}

Solution steps

Find the slope of

2 x y^{3} + x y = 18 : \frac{d y}{d x} = \frac{- y - 2 y ^{3}}{x ( 1 + 6 y ^{2} )}

Compute the slope of

2 x y^{3} + x y = 18

(6, 1) : m = - \frac{1}{14}

Find the line with slope m=

- \frac{1}{14}

and passing through

(6, 1) : y = - \frac{1}{14} x + \frac{10}{7}

y = - \frac{1}{14} x + \frac{10}{7}

\frac{1}{e ^{j t}}

\frac{d}{d x} (e^{x} (x - 9))

\frac{d}{d x} (\frac{x ^{5} + 5}{x ^{3}})

4 x^{2} + 10, 2 x + 7, - 3, 2

\frac{d}{d x} (3 x^{2} + \frac{1}{x ^{2}})

What is the tangent of 2xy^3+xy=18,(6,1) ?
The tangent of 2xy^3+xy=18,(6,1) is y=-1/14 x+10/7