What is the limit as x approaches 2 of (x^2+2x-8)/(3x-6) ?

The limit as x approaches 2 of (x^2+2x-8)/(3x-6) is 2

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limit as x approaches 2 of (x^2+2x-8)/(3x-6)

x \to 2 lim (\frac{x ^{2} + 2 x - 8}{3 x - 6})

2

Solution steps

x \to 2 lim (\frac{x ^{2} + 2 x - 8}{3 x - 6})

Simplify

\frac{x ^{2} + 2 x - 8}{3 x - 6} : \frac{1}{3} (x + 4)

= x \to 2 lim (\frac{1}{3} (x + 4))

Plug in the value

x = 2

= \frac{1}{3} (2 + 4)

Simplify

\frac{1}{3} (2 + 4) : 2

= 2

y^{^{'}} + (2 - \frac{x}{x - 1}) y = 0

x \to 1 lim (\frac{I n ( x )}{x - 1})

y = 8 e^{x} cos (x), (0, 8)

\frac{\partial}{\partial y} (x^{y^{2}})

What is the limit as x approaches 2 of (x^2+2x-8)/(3x-6) ?
The limit as x approaches 2 of (x^2+2x-8)/(3x-6) is 2