What is (\partial)/(\partial x)((x^2-1)*x^0) ?

The answer to (\partial)/(\partial x)((x^2-1)*x^0) is 2x

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(\partial)/(\partial x)((x^2-1)*x^0)

\frac{\partial}{\partial x} ((x^{2} - 1) \cdot x^{0})

2 x

Solution steps

\frac{\partial}{\partial x} ((x^{2} - 1) x^{0})

Simplify

(x^{2} - 1) x^{0} : x^{2} - 1

= \frac{\partial}{\partial x} (x^{2} - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) - \frac{\partial}{\partial x} (1)

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (1) = 0

= 2 x - 0

Simplify

= 2 x

\frac{\partial}{\partial x} (3 x^{2} + 6 y)

\frac{d}{d x} (- 0.5 x^{2})

g (x) = x^{5} + \frac{1}{x ^{5}}

x \to - 3 + lim (\frac{1}{x ^{2} - 9})

(1, - 19), (- 2, - 7)

What is (\partial)/(\partial x)((x^2-1)*x^0) ?
The answer to (\partial)/(\partial x)((x^2-1)*x^0) is 2x