What is the solution for x(dy)/(dx)+5y=x^3-x ?

The solution for x(dy)/(dx)+5y=x^3-x is y=(x^3)/8-x/6+(c_{1})/(x^5)

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x(dy)/(dx)+5y=x^3-x

x \frac{d y}{d x} + 5 y = x^{3} - x

y = \frac{x ^{3}}{8} - \frac{x}{6} + \frac{c _{1}}{x ^{5}}

Solution steps

x \frac{d y}{d x} + 5 y = x^{3} - x

Solve linear ODE:

y = \frac{x ^{3}}{8} - \frac{x}{6} + \frac{c _{1}}{x ^{5}}

y = \frac{x ^{3}}{8} - \frac{x}{6} + \frac{c _{1}}{x ^{5}}

7 e^{x}, 7 x e^{x^{2}}, 0, 1

\frac{d}{d x} (2 x^{4} - 5 x^{3} + 4)

h \to 0 lim (- 2 x - h + 3)

\frac{d}{d x} (3 cos (4 x) + sin (4 x))

x = 1, x = 3, y = x^{3} - 8, y = 0

What is the solution for x(dy)/(dx)+5y=x^3-x ?
The solution for x(dy)/(dx)+5y=x^3-x is y=(x^3)/8-x/6+(c_{1})/(x^5)