en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2y^'-x=1+y+xy

Solution

x^{2} y^{^{'}} - x = 1 + y + x y

Solution

y = e^{- \frac{1}{x} + c_{1}} x - 1

Solution steps

x^{2} y^{'} (x) - x = 1 + y + x y

Solve separable ODE:

y = e^{- \frac{1}{x} + c_{1}} x - 1

y = e^{- \frac{1}{x} + c_{1}} x - 1

Popular Examples

integral from-1 to 3 of (5-1/4 x^3)

\int_{- 1}^{3} (5 - \frac{1}{4} x^{3}) d x

integral of (7x^2)/(1+x^6)

\int \frac{7 x ^{2}}{1 + x ^{6}} d x

(x^2y^2-x^4)y^'=x^2y^2-y^4

(x^{2} y^{2} - x^{4}) y^{^{'}} = x^{2} y^{2} - y^{4}

limit as x approaches-1 of ln(1+x)

x \to - 1 lim (ln (1 + x))

derivative of ln(4x-5)

\frac{d}{d x} (ln (4 x - 5))

Frequently Asked Questions (FAQ)

What is the solution for x^2y^'-x=1+y+xy ?
The solution for x^2y^'-x=1+y+xy is y=e^{-1/x+c_{1}}x-1