What is the solution for y^'= 1/10 y(500-y) ?

The solution for y^'= 1/10 y(500-y) is y=(50)/(e^{-50t-c_{1)}-1}

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y^'= 1/10 y(500-y)

y^{^{'}} = \frac{1}{10} y (500 - y)

y = \frac{50}{e ^{- 50 t - c_{1}} - 1}

Solution steps

y^{'} (t) = \frac{1}{10} y (500 - y)

Solve Bernoulli ODE:

y = \frac{50}{e ^{- 50 t - c_{1}} - 1}

y = \frac{50}{e ^{- 50 t - c_{1}} - 1}

x^{5}, x = 2

y = x^{2} + 3 x + 11

\frac{3}{1 + 3 x}

\int x 5 + 2 x d x

\frac{d}{d x} (2 sin (x) - cos (2 x))

What is the solution for y^'= 1/10 y(500-y) ?
The solution for y^'= 1/10 y(500-y) is y=(50)/(e^{-50t-c_{1)}-1}