What is the integral of (x^9)/(1+x^{20)} ?

The integral of (x^9)/(1+x^{20)} is 1/10 arctan(x^{10})+C

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integral of (x^9)/(1+x^{20)}

\int \frac{x ^{9}}{1 + x ^{20}} d x

\frac{1}{10} arctan (x^{10}) + C

Solution steps

\int \frac{x ^{9}}{1 + x ^{20}} d x

Apply u-substitution

: \int \frac{1}{10 ( 1 + u ^{2} )} d u

= \int \frac{1}{10 ( 1 + u ^{2} )} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{10} \cdot \int \frac{1}{1 + u ^{2}} d u

Use the common integral:

\int \frac{1}{1 + u ^{2}} d u = arctan (u)

= \frac{1}{10} arctan (u)

Substitute back

u = x^{10}

= \frac{1}{10} arctan (x^{10})

Add a constant to the solution

= \frac{1}{10} arctan (x^{10}) + C

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What is the integral of (x^9)/(1+x^{20)} ?
The integral of (x^9)/(1+x^{20)} is 1/10 arctan(x^{10})+C