What is the integral from 2 to infinity of ye^{-5y} ?

The integral from 2 to infinity of ye^{-5y} is (11)/(25e^{10)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 2 to infinity of ye^{-5y}

\int_{2}^{\infty} y e^{- 5 y} d y

\frac{11}{25 e ^{10}}

Decimal Notation

0.00001 \dots

Solution steps

\int_{2}^{\infty} y e^{- 5 y} d y

Compute the indefinite integral:

\int y e^{- 5 y} d y = \frac{1}{25} (- 5 e^{- 5 y} y - e^{- 5 y}) + C

Compute the boundaries:

\int_{2}^{\infty} y e^{- 5 y} d y = 0 - (- \frac{11}{25 e ^{10}})

= 0 - (- \frac{11}{25 e ^{10}})

Simplify

= \frac{11}{25 e ^{10}}

(\frac{1}{14 x ^{2}}), x, (\frac{x}{4})

90 x

\frac{\partial}{\partial y} (- y sin (x))

\int_{- 2}^{2} \frac{3}{2} x^{2} d x

x \to 1 lim (- x^{2} + 4 x)

What is the integral from 2 to infinity of ye^{-5y} ?
The integral from 2 to infinity of ye^{-5y} is (11)/(25e^{10)}