What is the derivative of x^2+sin(x) ?

The derivative of x^2+sin(x) is 2x+cos(x)

What is the first derivative of x^2+sin(x) ?

The first derivative of x^2+sin(x) is 2x+cos(x)

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\frac{d}{d x} (x^{2} + sin (x))

2 x + cos (x)

Solution steps

\frac{d}{d x} (x^{2} + sin (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (sin (x))

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (sin (x)) = cos (x)

= 2 x + cos (x)

x y^{2} \frac{d y}{d x} = y^{3} - x^{3}

36 x^{2} - 48 x

ln (x) + 1

((sin (x))^{2})^{^{'}}

4 (\frac{1}{s ^{3}})

What is the derivative of x^2+sin(x) ?
The derivative of x^2+sin(x) is 2x+cos(x)
What is the first derivative of x^2+sin(x) ?
The first derivative of x^2+sin(x) is 2x+cos(x)